How do you figure sq inches of wing area?
From : Don Stackhouse
For a rectangular wing, it's just chord times span. For a single-tapered
(i.e.: trapezoidal) wing, it's (root chord + tip chord)/2 times the span.
For something more complicated than a single-tapered trapezoid, just break
up the shape into a series of trapezoids that approximate the shape well,
figure the area of each trapezoid and add them all up. The accuracy of this
method depends on how well the trapezoids approximate the actual shape.
CAD systems on computers use a variation of this method. They divide the
shape into a series of rectangular strips and add up the areas of the
rectangles. The reason it works is because they can divide the shape up
into MANY rectangles. For exampler, if I was finding the area of an
elliptical wing with highly rounded tips, I might tell the CAD system to
use strips only .005" or even .001" wide. Thousands of strips, but together
they make a very close approximation of the true shape, with the calculated
area accurate within a tiny fraction of a square inch. I sure wouldn't want
to try it that way with just pencil and paper though!
That depends on a great many other factors. The formula for lift of an
infinite-span wing is:
L = 1/2 Cl rho V^2 S
where L = lift
the 1/2 is leftover from the equation that this one originally came from
Cl = "lift coefficient", which depends on airfoil and angle of attack
rho = air density
V^2 = velocity squared
S = wing area
As you can see, if you fly higher where the air is thinner (and therefore
the density is lower), you don't get as much lift. OTOH, more area, a
different airfoil or angle of attack, or especially an increase in airspeed
can make a lot more lift.
Cl depends primarily on the shape of the airfoil, the angle of attack it's
flying at, and on the Reynolds number or "Re", which is a measure of what
we call scale effect. It depends on chord length, speed, air density and on
air viscosity (the stickyness or slipperyness of the air; maple syrup and
peanut butter have high viscosity, water has lower viscosity, and air's
viscosity is even lower). To calculate Re at sea level, multiply 778 times
the chord in inches times the sped in miles per hour. Smaller airfoils like
the ones on our models make more drag and less lift than the same airfoils
would on something larger or faster. In addition, each airfoil shape will
have a certain range of Re's where it works best. The airfoils that work
well on full-scale usually do not work well on models, and model airfoils
usually do not work well on full scale aircraft. The airfoils that do well
on "conventional" R/C models are usually inappropriate for our slow fliers.
The details of why and how this is are very complex, and can fill books. I
won't go much further into it here, but there is some more discussion of
this in some of the articles in the "Ask Joe and Don" section of our website:
http://www.bright.net/~djwerks/
For typical airfoils for indoor models, an efficient Cl is likely to be
somewhere around .2 to .6, maybe .8 to .9 for a good airfoil design working
close to stall. Yes, it is possible to get somewhat higher than that, but
with few exceptions, the drag is going to get very high. More drag means
more power required, which means bigger batteries, which negates the
increase in lift. In addition, the turns we make are so tight that the
inside wingtip gets into stall problems if we don't leave it some reserve
capability. For preliminary design purposes, I'd recommend trying to stay
under about .6 to .8 maximum unless there's some solid data indicating it's
safe to go higher. I have designs that can do much better than that, but it
takes a lot of very good design tools plus a LOT of experience using them
to achieve that.
Then there's the effects of finite span. Most of us don't have room in our
storage area to keep an infinite span wing, so we have to opt for a span
that's somewhat less than that. The problem with a finite span wing is that
the air spills around the tips, so the lift is reduced. How much it's
reduced depends on the details of the each specific wing design, but for
typical indoor models we could reasonably assume it's about 75% to 85% of
the lift of an infinite span wing of the same area. That means that our Cl
limits of .6 to .8 that I discussed above become only .45 to .68 when you
throw in the effects of a finite span wing. Once again, the right design
tools and the experience to back them up can do much better, but very few
folks have access to that sort of design capability, nor the obsessiveness
to go through all the work required to make it happen. If you want to
stick to just rules of thumb and cookbook airfoils and planforms, you'd
better assume conservative values for Cl.
Now let's talk about rho, the air density. In English units it's measured
in slugs, and at sea level standard conditions it's about .002378 slugs. At
2500 feet msl ("above Mean Sea Level") it drops to .002209 slugs, and it's
down to .002049 on a standard day at 5000 msl in Denver. Meanwhile, the
viscosity stays nearly constant, so as you gain altitude you also get lower
Reynolds numbers, which in turn reduces Cl. It's a double whammy, we lose
both Cl and rho as we go higher, so it's no wonder that models that are
marginal performers at sea level in Santa Barbara sometimes become
flightless R/C cars in Denver or Reno. Also, a hot day reduces the air
density as well. For example, here in Ohio at about 1000 msl, the air
density on a hot day in August can approximate the standard day density of
a 3000 msl altitude.
For the formula and numbers above, you should use feet per second for
velocity and square feet for wing area. To convert miles per hour to feet
per second, multiply by 22 and divide by 15.
Frank, we're now finally ready to answer your question!
Let's assume we have an effective Cl for the whole wing of .6, and we're
flying at a density altitude of 2500 feet msl.
At 5 mph at these conditions, a square foot (144 square inches) of wing
will support .0356 pounds, which is .57 ounces.
At 6 mph, that increases to .82 ounces.
At 7 mph, it can support 1.11 ounces.
At 10 mph, it can support 2.28 ounces.
At 15 mph, it can support 5.13 ounces.
At 20 mph, it can support 9.12 ounces.
Those advertising claims of indoor models with 4 mph flying speeds are
starting to look a bit questionable, aren't they! It is possible to fly
that slowly with a heavier-than-air fixed-wing model, but it's extremely
difficult. I'd say in most cases, about 7 mph or more is probably more
reasonable. That's still pretty dog-gone slow.
Don Stackhouse
DJ Aerotech
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